django - escape % character in Python -
django - escape % character in Python -
i have next string in python, rendered in template django.
link_string = '<a href="/search/?q=%23%s"> %s </a>'
it link search url %23 '#', because i'm trying search objects #hashtag.
i intend interpolate string 2 values, %s after %23 , one:
link_href = link_string % ('hashtag_value', 'link name')
what proper way obtain next final string:
<a href="/search/?q=%23hashtag_value"> link name </a>
thank much
link_string = '<a href="/search/?q=%%23%s"> %s </a>'
python django string escaping design-patterns
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