knockout.js - How do I swap two items in an observableArray? -



knockout.js - How do I swap two items in an observableArray? -

i have button moves item 1 position left in observablearray. doing next way. however, drawback categories()[index] gets removed array, discarding whatever dom manipulation (by jquery validation in case) on node.

is there way swap 2 items without using temporary variable preserve dom node?

moveup: function (category) { var categories = viewmodel.categories; var length = categories().length; var index = categories.indexof(category); var insertindex = (index + length - 1) % length; categories.splice(index, 1); categories.splice(insertindex, 0, category); $categories.trigger("create"); }

here's version of moveup swap in 1 step:

moveup: function(category) { var = categories.indexof(category); if (i >= 1) { var array = categories(); categories.splice(i-1, 2, array[i], array[i-1]); } }

that still doesn't solve problem, though, because knockout still see swap delete , add together action. there's open issue knockout back upwards moving items, though. update: of version 2.2.0, knockout recognize moved items , foreach binding won't re-render them.

knockout.js

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