c++ - ideone doesn't show any output -
c++ - ideone doesn't show any output -
this code of problem http://www.spoj.com/problems/base/ , runs fine on windows , linux when run on ideone not show me output. can tell me reason behind this?
#include<stdio.h> #include<math.h> #include<string.h> #include<string> #include<iostream> using namespace std; long int convert_base10(char *num, int base) { int len, dig; long int result = 0; len = strlen(num); // printf("len = %d\n", len); // converting base of operations 10 for(int i=0; i<len; i++) { if((num[len-i-1] >= 'a') && (num[len-i-1] <= 'f')) dig = num[len-i-1] - 55; else dig = num[len-i-1] - 48; result += (dig * pow(base, i)); // printf("num[%d] = %d\n", len-i-1, dig); } homecoming result; } void convert_basei(long int num, int base, string &result1) { bool error = false; int pos = 6; char result[7], rem; // storing space on position for(int i=0; i<7; i++) result[i] = ' '; while(num) { if((num % base) >= 10) rem = (num % base) + 55; else rem = (num % base) + 48; result[pos] = rem;//printf("result[%d] = %c\n", pos, rem); num /= base;// printf("quotient = %d\n", num); pos--; if(pos < 0 && num > 0) { error = true; break; } } if(error == true) result1 = " error"; else result1 = result; // cout<<"result = "<<result1<<endl; } int main() { char num[7]; string result; int base1, base2; while(scanf("%s%d%d", num, &base1, &base2) == 3) { // printf("num = %s\nbase1 = %d\nbase2 = %d\n", num, base1, base2); long int temp = convert_base10(num, base1); // printf("temp = %ld\n", temp); convert_basei(temp, base2, result); cout<<result<<endl; } homecoming 0; }
replace code:
while(scanf("%s%d%d", num, &base1, &base2) == 3) { long int temp = convert_base10(num, base1); convert_basei(temp, base2, result); cout<<result<<endl; }
with code, , mystery go away:
printf("trying input\n"); while(scanf("%s%d%d", num, &base1, &base2) == 3) { printf("got input\n"); long int temp = convert_base10(num, base1); convert_basei(temp, base2, result); cout<<result<<endl; } printf("got no input\n");
c++
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